Explain this then. My parents house before they bought it had damp which was called 'rising damp' going by visual inspection and by the surveyor at the time. My parents called this company in to inject the walls at dpc level. Somehow the damp never ever appeared again in the 15-20 years we lived in it. Explain that!
Simple !
Take a brick and put it in trey with water, even better, use 2 with anything in between. Leave it outside , but put something on top to ensure the bricks are exposed to water only beneath. Monitor it for a few days or a week. Now do the same thing but put something on top that will close it tight like greenhouse. After a few sunny days have a look and report back
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If that's too simple for you.......here is some real headache for you
Capillary action
The rise of a column of liquid within a fine capillary tube is also due to surface tension. Capillary action causes liquid to soak upwards through a piece of blotting paper and it also partly explains the rise of water through the capillaries in the stems of plants. (In this last case osmotic pressure accounts for a large part of the rise.)
There are two alternative proofs for the formula for capillary rise and we will consider Figure 1(a) first.
Let the radius of the glass capillary tube be r, the coefficient of surface tension of the liquid he T, the density of the liquid be ρ, the angle of contact between the liquid and the walls of the tube be θ and the height to which the liquid rises in the tube be h.
Consider the circumference of the liquid surface where it meets the glass.
Along this line the vertical component of the surface tension force will be 2πr cosθT.
This will draw the liquid up the tube until this force by the downward force due to the column of liquid of height h, that is just balanced at equilibrium:
Therefore
2πr cosθ T = πr2ρgh which gives
Capillary rise (h) = [2T cosθ]/[rρg]
Which for an angle of contact of 0o becomes:
Capillary rise (h) = 2T/[rρg]
For the alternative proof consider Figure 1(b). We will assume that if the radius of the tube is small the shape of the liquid surface is very nearly hemispherical.
The pressure at A must be atmospheric, but since A is within a hemispherical surface the pressure at B must be less than A by an amount 2T/r. The pres
sure at C is also atmospheric but it is greater than the pressure at B by the hydrostatic pressure hρg. Therefore at equilibrium we have h = 2T/rrg, as above.
Both these methods show that the rise is greater in tubes with a narrow bore and for zero angles of contact. In fact when the coefficient of surface tension is measured by capillary rise in the laboratory the values obtained are nearly always too small because of the difficulty of getting perfectly clean apparatus. The angle of contact can rarely be made zero.
With a mercury-glass surface the angle of contact is >90o and therefore cosθ is negative. This means that the mercury level is not raised but depressed below the level of the surrounding liquid.
Example problem
Calculate the radius of a capillary tube if water rises to a height of 12.5 cm within it, assuming the angle of contact between the water and glass to be 0o.
Using the formula: h = 2T/rρg
Radius of tube (r) = 2T/hρg = [2 x 72.7 x 10-3]/0.125x 1000 x 9.8 = 1.2x10-4 m = 0.12 mm
Hope that helps
No fcuking chance! 
! Can't imagine this place without the hottest topic! 
, which can put you even deeper in the dark by the way 